21y^4+28y^2=

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Solution for 21y^4+28y^2= equation:


Simplifying
21y4 + 28y2 = 0

Reorder the terms:
28y2 + 21y4 = 0

Solving
28y2 + 21y4 = 0

Solving for variable 'y'.

Factor out the Greatest Common Factor (GCF), '7y2'.
7y2(4 + 3y2) = 0

Ignore the factor 7.

Subproblem 1

Set the factor 'y2' equal to zero and attempt to solve: Simplifying y2 = 0 Solving y2 = 0 Move all terms containing y to the left, all other terms to the right. Simplifying y2 = 0 Take the square root of each side: y = {0}

Subproblem 2

Set the factor '(4 + 3y2)' equal to zero and attempt to solve: Simplifying 4 + 3y2 = 0 Solving 4 + 3y2 = 0 Move all terms containing y to the left, all other terms to the right. Add '-4' to each side of the equation. 4 + -4 + 3y2 = 0 + -4 Combine like terms: 4 + -4 = 0 0 + 3y2 = 0 + -4 3y2 = 0 + -4 Combine like terms: 0 + -4 = -4 3y2 = -4 Divide each side by '3'. y2 = -1.333333333 Simplifying y2 = -1.333333333 The solution to this equation could not be determined. This subproblem is being ignored because a solution could not be determined.

Solution

y = {0}

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